If you have them one after another i.e. in Series, the first one takes some current to work, then the other takes some more current but less is available because oif the first and so on...
You could have done it like this:
Which is putting them in Parallel to each other, where they all get the same amount of current
This is a good site for calculating the resistor you need for series or parallel LED's.
i really have no idea where to place them in a circuit how many or n e thing at all treat me as a complete noob is there any pages you have that could guide me, i just use 3V batteries with 3V LEDs lol simple
An LED has one leg slightly longer than the other, the longer leg is the + side, the shorter led the - side. The wires go from the + of the battery, to the resistor (but only if its more than 3v from the battery) and then from the other side of the resistor, the wires go to the longest leg of each LED, and then the wires go from the other leg of the LED to the - of the battery...
LEDs are current sensitive. Too much current will over drive them either leading to a shortened life time or end it abruptly and with a bang. The dropping resistor is to limit the amount of current the led draws. It doesn't matter if it's a battery or 110 from the wall, you'll need to limit the current. How you wire them can bypass the need for a dropping resistor. A series/parallel connection would normally do the trick. Most will light up at around 20miliamps and get brighter as the current ramps up. But if you over drive one you better be standing back from it. They have a nasty habit of exploding like a popcorn kernel spewing hot shards of plastic.
long an short.
yes this is possible.
someone alreay gave the pinnout.
you can run the LEDs (assuming that you use 5v LEDs) straight from the power lines.
though LEDs have quite a low forward bias resistance and will draw a lot of current from the bus.
so it's really recommended that you use a current limiting resistor regardles of whether you use 3.3v or 5v (or 12v LEDs).