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Old 12-13-2009, 10:06 PM   #1
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Default sec(tan^-1(4/3))^2=25/9

Could someone explain why that is?
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Old 12-13-2009, 10:30 PM   #2
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Default Re: sec(tan^-1(4/3))^2=25/9

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Old 12-13-2009, 11:14 PM   #3
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Default Re: sec(tan^-1(4/3))^2=25/9

You mean tan(4/3*pi)?

hmm, nvm, 4/3pi doesnt get me that answer.

I have no idea, I think that might be false.
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Old 12-13-2009, 11:48 PM   #4
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Default Re: sec(tan^-1(4/3))^2=25/9

It checks correctly.

The inverse tangent of 4/3, denoted as tan^-1(4/3), is equal to approximately .9273 radians. This value is a little less than pi/3. Then, when you take the square of the secant of that value, denoted by (sec(.9237))^2, you get 25/9. What that statement says is the following:

The square of the secant whose angle gives a slope of 4/3 is 25/9.

Remember that secant is 1/cos. Make sure to type all of the parenthesis correctly in your calculator.
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Old 12-13-2009, 11:56 PM   #5
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Default Re: sec(tan^-1(4/3))^2=25/9

Quote:
Originally Posted by JogaBonito1502 View Post
It checks correctly.

The inverse tangent of 4/3, denoted as tan^-1(4/3), is equal to approximately .9273 radians. This value is a little less than pi/3. Then, when you take the square of the secant of that value, denoted by (sec(.9237))^2, you get 25/9. What that statement says is the following:

The square of the secant whose angle gives a slope of 4/3 is 25/9.

Remember that secant is 1/cos. Make sure to type all of the parenthesis correctly in your calculator.
I got the the problem by myself up until the "sec".
What is Secant?


EDIT: Google is my friend.

Hm. Okay so it's hypotenuse over adjacent. Alrighty.
Haven't learned that yet I only have worked with sin, tan, and cos.
and of course also the inverse of all of those.
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Old 12-14-2009, 12:16 AM   #6
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Default Re: sec(tan^-1(4/3))^2=25/9

Quote:
Originally Posted by JogaBonito1502 View Post
It checks correctly.

The inverse tangent of 4/3, denoted as tan^-1(4/3), is equal to approximately .9273 radians. This value is a little less than pi/3. Then, when you take the square of the secant of that value, denoted by (sec(.9237))^2, you get 25/9. What that statement says is the following:

The square of the secant whose angle gives a slope of 4/3 is 25/9.

Remember that secant is 1/cos. Make sure to type all of the parenthesis correctly in your calculator.
tan(x)^-1 would be 1/tan(x) correct? And 1/tan(4/3) is not .9273....
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Old 12-14-2009, 12:21 AM   #7
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Default Re: sec(tan^-1(4/3))^2=25/9

Quote:
Originally Posted by superman22x View Post
tan(x)^-1 would be 1/tan(x) correct? And 1/tan(4/3) is not .9273....
You're mistaken.

1/tan(x) = cot(x); where x is an angle measurement
tan^-1(x) = y; where x is an number and y is an angle measurement such that tan (y) = x
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Old 12-14-2009, 12:26 AM   #8
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Default Re: sec(tan^-1(4/3))^2=25/9

Oh, yeah, mixed up, lol.
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Old 12-14-2009, 01:36 AM   #9
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Default Re: sec(tan^-1(4/3))^2=25/9

ya, i sure as hell have no idea what your all talking about lol
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Old 12-14-2009, 01:52 PM   #10
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Default Re: sec(tan^-1(4/3))^2=25/9

Banned for Spam!

P.S What am I looking at?
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