Maths Question Driving Me Insane

[Nik00117]

Looks like out of my league

 

[jac006]

I think the answer is 1,000,000 honestly... I did it and that's what I got...

 

[root]

Yeah, I noticed that, too. I was like.... wait, n^2 = n?????? WTF? Which n do they want? But yeah, Stacey has it right. The first n would be 1000, and the second n would be 1,000,000 (one million). Root - your logic is correct, but you messed up a bit on your math. 1999/2 + 0.5 = 1000, not 500. Anyway, you guys are basically doing the same thing, just in a different order. Stacy's method is probably a bit easier, but they both work out the same way.

sorry to bring this back up again...

but I've been away all weekend having an awesome birthday... I just have to tell you that I didn't mess up in my calculations, and the equations both me and stacy posted were correct...

however it was stacy who made the small mistake... (when writting the answer to the equation).

((1+1999)/2)sqr != 1000 sqr

1999/2 + 0.5 also !=1000 (it does == 500!!!)

1999 / 2 + 0.5 = 499.5 + 0.5 = 500 (multiplication and division takes precidence, which is why stacys equation used brackets...)

anyway, now back to the mistake...
((1+ 1999)/2) = ((1000)/2) = 500 != 1000

 

[eTech|Stacy]

sorry to bring this back up again...

but I've been away all weekend having an awesome birthday... I just have to tell you that I didn't mess up in my calculations, and the equations both me and stacy posted were correct...

however it was stacy who made the small mistake... (when writting the answer to the equation).

((1+1999)/2)sqr != 1000 sqr

1999/2 + 0.5 also !=1000 (it does == 500!!!)

1999 / 2 + 0.5 = 499.5 + 0.5 = 500 (multiplication and division takes precidence, which is why stacys equation used brackets...)

anyway, now back to the mistake...
((1+ 1999)/2) = ((1000)/2) = 500 != 1000

I think 1+1999=2000 not 1000!

 

[root]

ahhh, bugger... in the original equation I wrote, (on paper) 999 not 1999...

my mistake, sorry.

 

[lhuser]

What level of math is this?!?

 

[catalyst1]

ahhh, bugger... in the original equation I wrote, (on paper) 999 not 1999...

my mistake, sorry.

Hehe, I was gonna say! We all make mistakes though. No big deal. And to lhuser - it's a pretty basic level of math. The original problem is more analytical than the usual easy problems, but the math involved is not difficult.