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Old 10-30-2005, 12:08 PM   #1
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Default Maths homework (yes, I know!)

I know I shouldn't be asking.

Gah, Maths is so pointless, but I'm stuck with it until January. Can anybody help me out?

I've got to Show that:

a) (1-cosēt)(1+cotanēt)=1

b) tanθ + cotanθ = 1/ cosθsinθ

c) sinθtanθ+cosθ = secant θ

I don't need to solve the equations or find any values, I've just got to show the statements are true. I don't know where to start with these three buggers.

Anybody? Pointless trig is my main sticking point. Any ideas?
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Old 10-30-2005, 12:36 PM   #2
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Default Re: Maths homework (yes, I know!)

well u can prove them right by calculating them.
Sin, Cos and Tan are angles, u need to have a calculator which knows these. If u don't u can use the one on windows.

Other than that it goes beyond my understanding.
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Old 10-31-2005, 04:13 AM   #3
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Default Re: Maths homework (yes, I know!)

a)
(1-cosēt)(1+cotanēt)=1
(1-(1-sinēt))(1+(cscēt-1))=1
(sinēt)(cscēt)=1
sinēt(1/sinēt)=1
1=1

b)
tan(t) + cotan(t) = 1/(cos(t)sin(t))
sin(t)/cos(t) + cos(t)/sin(t) = 1/(cos(t)sin(t))
sinē(t)/(sin(t)cos(t)) + cosē(t)/(sin(t)cos(t)) = 1/(cos(t)sin(t))
(sinē(t) + cosē(t))/(sin(t)cos(t)) = 1/(cos(t)sin(t))
1/(sin(t)cos(t)) = 1/(cos(t)sin(t))

c)
sin(t)tan(t) + cos(t) = sec(t)
sin(t)(sin(t)/cos(t)) + cos(t) = sec(t)
sinē(t)/cos(t) +cosē(t)/cos(t) = sec(t)
(sinē(t) + cosē(t))/cos(t) = sec(t)
1/cos(t) = sec(t)
sec(t) = sec(t)
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Old 10-31-2005, 04:15 AM   #4
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Default Re: Maths homework (yes, I know!)

please delete this post
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Old 10-31-2005, 07:53 AM   #5
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Default Re: Maths homework (yes, I know!)

sooo much to do...>_<
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Old 10-31-2005, 11:51 AM   #6
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Default Re: Maths homework (yes, I know!)

It's not too hard as long as you know your trig identities.
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