

03222007, 01:54 PM

#1

Golden Master
Join Date: Nov 2004
Posts: 8,632

maths help needed asap!
i have some tricky work to do. i dont understand it at all. i need to do it asap. heres an example of a qu i need help with. (see question b)
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03222007, 03:11 PM

#2

Golden Master
Join Date: Sep 2006
Posts: 7,883

Re: maths help needed asap!
Eh, sorry, we haven't done logs yet.
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03222007, 05:59 PM

#3

Golden Master
Join Date: Nov 2004
Posts: 8,632

Re: maths help needed asap!
ok. i guess ill have to spend an hour tomorrow in the "support session" lol. i still wont finish it. nothing i can do about it though. maths is v hard and she storms through the work. thats why im failing
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03222007, 06:03 PM

#4

Golden Master
Join Date: Oct 2005
Posts: 7,846

Re: maths help needed asap!
Is that GCSE higher?



03222007, 06:09 PM

#5

BSOD
Join Date: Apr 2005
Posts: 6,556

Re: maths help needed asap!
google it lol....



03222007, 06:52 PM

#6

Golden Master
Join Date: Nov 2004
Posts: 8,632

Re: maths help needed asap!
Quote:
Originally Posted by rudster816
google it lol....

i tried lol. failed.... its first year a level. i used to get a's easily in gsce. now in alevel i struggle to get c's. its fcuked up
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03222007, 08:59 PM

#7

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Join Date: Mar 2006
Posts: 5,574

Re: maths help needed asap!
all logarithms are is a fancy way of writing a power. what happens is the that base of the log is 10, which would be 10 raised to a power. the number the follows the log is the answer, so when you do the log of 4 on your calculator, you are finding 10^what ever power=4.
to help with those two problems, what you need to do is remember the fact that logs are exponents. so if you have 2log4=x, it is also equalivent to log16=x. that can also be reversed, and log100 would be 2log10.
the first one, what you would do is take the log of both sides, so you get:
log(a^x)=log(10^[2x+1])
which with what I stated above can be simplified to:
x*log(a)=2x+1*log(10)
being that logarithms have a given base of 10 (except for natural logs ln, and logs with subscript after them that specifies the base) you now have:
x*log(a)=)2x+1)*1
which with some basic math, you finally get
log(a)=x+.5
and again using the rule of logs from the second paragraph you get:
a=10^(x+.5)
now b is a little more complex looking, but it is the same concept. You have to remember that logs can be added, subtracted, and multiplied just like exponents.
2*log(2x)=1+log(a)
subtract 1 from each side
2*log(2x)1=log(a)
now just use the fundamental rule of logs to get:
a=10^(2*log(2x)1)
and there you go.
hope this helps.
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03222007, 09:13 PM

#8

Golden Master
Join Date: May 2006
Posts: 7,903

Re: maths help needed asap!
Hmm, we just did logs, but Im in high school advanced algebra 2 and didnt do stuff quite this complex.
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03232007, 01:07 PM

#9

Golden Master
Join Date: Nov 2004
Posts: 8,632

Re: maths help needed asap!
Quote:
Originally Posted by wood_workur
all logarithms are is a fancy way of writing a power. what happens is the that base of the log is 10, which would be 10 raised to a power. the number the follows the log is the answer, so when you do the log of 4 on your calculator, you are finding 10^what ever power=4.
to help with those two problems, what you need to do is remember the fact that logs are exponents. so if you have 2log4=x, it is also equalivent to log16=x. that can also be reversed, and log100 would be 2log10.
the first one, what you would do is take the log of both sides, so you get:
log(a^x)=log(10^[2x+1])
which with what I stated above can be simplified to:
x*log(a)=2x+1*log(10)
being that logarithms have a given base of 10 (except for natural logs ln, and logs with subscript after them that specifies the base) you now have:
x*log(a)=)2x+1)*1
which with some basic math, you finally get
log(a)=x+.5
and again using the rule of logs from the second paragraph you get:
a=10^(x+.5)
now b is a little more complex looking, but it is the same concept. You have to remember that logs can be added, subtracted, and multiplied just like exponents.
2*log(2x)=1+log(a)
subtract 1 from each side
2*log(2x)1=log(a)
now just use the fundamental rule of logs to get:
a=10^(2*log(2x)1)
and there you go.
hope this helps.

cheers dude. i think i might save this for future reference :P
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03232007, 03:44 PM

#10

Golden Master
Join Date: Mar 2006
Posts: 5,574

Re: maths help needed asap!
no problem.
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