

03222007, 12:54 PM

#1

Golden Master
Join Date: Nov 2004
Posts: 8,632

maths help needed asap!
i have some tricky work to do. i dont understand it at all. i need to do it asap. heres an example of a qu i need help with. (see question b)
__________________
__________________
Laptop spec: ASUS X53E, i5 2430m 2.4ghz, 3gb ram, 320gb hdd, intel hd graphics, usb 3.0



03222007, 02:11 PM

#2

Golden Master
Join Date: Sep 2006
Posts: 7,883

Re: maths help needed asap!
Eh, sorry, we haven't done logs yet.
__________________
__________________
C2D E6600  4GB DDR2800  9800GTX+  Asus P5BE  150GB Raptor  320GB 7200.10  750W Xigmatek PSU



03222007, 04:59 PM

#3

Golden Master
Join Date: Nov 2004
Posts: 8,632

Re: maths help needed asap!
ok. i guess ill have to spend an hour tomorrow in the "support session" lol. i still wont finish it. nothing i can do about it though. maths is v hard and she storms through the work. thats why im failing
__________________
Laptop spec: ASUS X53E, i5 2430m 2.4ghz, 3gb ram, 320gb hdd, intel hd graphics, usb 3.0



03222007, 05:03 PM

#4

Golden Master
Join Date: Oct 2005
Posts: 7,846

Re: maths help needed asap!
Is that GCSE higher?



03222007, 05:09 PM

#5

BSOD
Join Date: Apr 2005
Posts: 6,556

Re: maths help needed asap!
google it lol....



03222007, 05:52 PM

#6

Golden Master
Join Date: Nov 2004
Posts: 8,632

Re: maths help needed asap!
Quote:
Originally Posted by rudster816
google it lol....

i tried lol. failed.... its first year a level. i used to get a's easily in gsce. now in alevel i struggle to get c's. its fcuked up
__________________
Laptop spec: ASUS X53E, i5 2430m 2.4ghz, 3gb ram, 320gb hdd, intel hd graphics, usb 3.0



03222007, 07:59 PM

#7

Golden Master
Join Date: Mar 2006
Posts: 5,574

Re: maths help needed asap!
all logarithms are is a fancy way of writing a power. what happens is the that base of the log is 10, which would be 10 raised to a power. the number the follows the log is the answer, so when you do the log of 4 on your calculator, you are finding 10^what ever power=4.
to help with those two problems, what you need to do is remember the fact that logs are exponents. so if you have 2log4=x, it is also equalivent to log16=x. that can also be reversed, and log100 would be 2log10.
the first one, what you would do is take the log of both sides, so you get:
log(a^x)=log(10^[2x+1])
which with what I stated above can be simplified to:
x*log(a)=2x+1*log(10)
being that logarithms have a given base of 10 (except for natural logs ln, and logs with subscript after them that specifies the base) you now have:
x*log(a)=)2x+1)*1
which with some basic math, you finally get
log(a)=x+.5
and again using the rule of logs from the second paragraph you get:
a=10^(x+.5)
now b is a little more complex looking, but it is the same concept. You have to remember that logs can be added, subtracted, and multiplied just like exponents.
2*log(2x)=1+log(a)
subtract 1 from each side
2*log(2x)1=log(a)
now just use the fundamental rule of logs to get:
a=10^(2*log(2x)1)
and there you go.
hope this helps.
__________________
AMD Athlon 64X2 4200+, 2 GB ram, 2 TB HDD, Ubuntu+SAMBA ♫ Lenovo T410, i5@ 2.4 GHz, 4 GB ram, 7



03222007, 08:13 PM

#8

Site Team
Join Date: May 2006
Posts: 7,903

Re: maths help needed asap!
Hmm, we just did logs, but Im in high school advanced algebra 2 and didnt do stuff quite this complex.
__________________
“Adults are just obsolete children and the hell with them.”  Dr. Suess



03232007, 12:07 PM

#9

Golden Master
Join Date: Nov 2004
Posts: 8,632

Re: maths help needed asap!
Quote:
Originally Posted by wood_workur
all logarithms are is a fancy way of writing a power. what happens is the that base of the log is 10, which would be 10 raised to a power. the number the follows the log is the answer, so when you do the log of 4 on your calculator, you are finding 10^what ever power=4.
to help with those two problems, what you need to do is remember the fact that logs are exponents. so if you have 2log4=x, it is also equalivent to log16=x. that can also be reversed, and log100 would be 2log10.
the first one, what you would do is take the log of both sides, so you get:
log(a^x)=log(10^[2x+1])
which with what I stated above can be simplified to:
x*log(a)=2x+1*log(10)
being that logarithms have a given base of 10 (except for natural logs ln, and logs with subscript after them that specifies the base) you now have:
x*log(a)=)2x+1)*1
which with some basic math, you finally get
log(a)=x+.5
and again using the rule of logs from the second paragraph you get:
a=10^(x+.5)
now b is a little more complex looking, but it is the same concept. You have to remember that logs can be added, subtracted, and multiplied just like exponents.
2*log(2x)=1+log(a)
subtract 1 from each side
2*log(2x)1=log(a)
now just use the fundamental rule of logs to get:
a=10^(2*log(2x)1)
and there you go.
hope this helps.

cheers dude. i think i might save this for future reference :P
__________________
Laptop spec: ASUS X53E, i5 2430m 2.4ghz, 3gb ram, 320gb hdd, intel hd graphics, usb 3.0



03232007, 02:44 PM

#10

Golden Master
Join Date: Mar 2006
Posts: 5,574

Re: maths help needed asap!
no problem.
__________________
__________________
AMD Athlon 64X2 4200+, 2 GB ram, 2 TB HDD, Ubuntu+SAMBA ♫ Lenovo T410, i5@ 2.4 GHz, 4 GB ram, 7





Thread Tools 
Search this Thread 


Display Modes 
Linear Mode

Posting Rules

You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts
HTML code is Off




» Recent Threads 
















