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Old 05-02-2006, 11:01 PM   #1
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Default math very odd

im doing distance formula right now and I keep getting prefect squares.
this is what ive done
square root of (40-40)^2+(18-60)^2
I got 42
can someone please check this to see if I did it wrong.
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Old 05-02-2006, 11:09 PM   #2
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Default Re: math very odd

nvm i got a way to check...lol i feel so stupid.
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Old 05-03-2006, 01:29 AM   #3
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Default Re: math very odd

Quote:
Originally Posted by GreatHype
square root of (40-40)^2+(18-60)^2
it is 42.

btw, your sig is a bit long.
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Old 05-03-2006, 06:55 AM   #4
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Default Re: math very odd

SQRT of (40-40)^2+(18-60)^2
= SQRT of (0)^2+(-42)^2
= SQRT of -42^2
= 42

negative numbers squared = postitive numbers.
you cant square a number and bring back a negative result

eg 1^2 = 1
-1^2 = 1
SQRT(1) = 1
SQRT(-1) = j (that's an imaginary (not real) number)
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Old 05-03-2006, 05:53 PM   #5
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Default Re: math very odd

lol ok thanks.
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Old 05-03-2006, 09:08 PM   #6
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Default Re: math very odd

no, actually, the sqare root of -1 is i, and imagionary number. You will learn more about that in Algebra2. Now go finish your geometry homework.
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Old 05-03-2006, 09:12 PM   #7
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Default Re: math very odd

im in algebra lol I take geometry next year. I'm doing my algebra hw right now and it sucks. I hate parabolas but good think I have omnigraph so I can check my work =)
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Old 05-03-2006, 10:42 PM   #8
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Default Re: math very odd

IF you square root a negative, it will give you an error. DO NOT try to do it if a question asks it. Just write impossible
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Old 05-03-2006, 10:44 PM   #9
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Default Re: math very odd

If a square root was negative, it'd give you a value of i which is imaginary...

For example:
SQUARE ROOT -49 is..
7i.
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Old 05-03-2006, 11:33 PM   #10
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Default Re: math very odd

in my case if the disciminant was negative I would automatically write no real solutions. We havent gotten to imaginary i's yet.
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