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Old 11-16-2005, 02:41 PM   #31
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Default Re: 1 = 2

AČ = AB
AČ - BČ = AB - BČ
(A + B)(A - B) = B(A - B)
A + B = B
B + B = B
2B = B
2 = 1


OK, I'll try doing it with numbers
A = B = 1

AČ = AB => 1*1 = 1*1 => 1
AČ - BČ = AB - BČ => 1 - 1 = 1-1 => 0
(A + B)(A - B) = B(A - B) = (1+1)(1-1) = 1(1-1) =>true 0=0!!! (sure enough!)

1+1 = 1 False...

OK, now I'll try with a different number

A = B = 2

AČ = AB => 2*2 = 2*2 => 4
AČ - BČ = AB - BČ => 4 - 4 = 4-4
(A + B)(A - B) = B(A - B) = (2+2)(2-2) = 2(2-2) =>True

(2+2)(2-2)=>2*2 + 2*2 -2*2 - 2*2 = 0
2(2*2) = 4-4 = 0

2+2 = 2 False...

Like I said...
Quote:
The fairytale maths starts here...

AČ - BČ = AB - BČ

since A = B all that = 0

2b = b => 2*0 = 0...


The line (A + B)(A - B) = B(A - B) only works because both sides are equal(and equal to zero).
taking it past that is impossible...

therefore the solution only has real answers if A and B = 0

the maths is fine, and can be solved, but like I said, it only has 1 possible real solution.


there are no imaginary solutions either, I just tried...
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Old 11-16-2005, 11:41 PM   #32
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Default Re: 1 = 2

Quote:
Originally Posted by root
A = B = 2

AČ = AB => 2*2 = 2*2 => 4
AČ - BČ = AB - BČ => 4 - 4 = 4-4
(A + B)(A - B) = B(A - B) = (2+2)(2-2) = 2(2-2) =>True
Well if u count it like this (Though I would count it like u did, which would then mean that the whole equation is wrong) but here we go

A=B=2
(A+B)(A-B) = B(A-B)
So that is (2+2)(2-2) = 2(2-2)
Then u take (2-2) away from both sides it becomes
(2+2) = 2
4=2
same as 2=1
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Old 11-17-2005, 12:28 AM   #33
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Default Re: 1 = 2

Quote:
Originally Posted by root
1+1 = 1 False...
But that's the whole point. This set of equations proves something that isn't true! Well, I'll tell you guys tomorrow.
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Old 11-17-2005, 01:42 AM   #34
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Default Re: 1 = 2

Lol what a bastard you are

Just thought i would say that if A=0 then the entire equation makes sence. 140A=A still =0 if A=0
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Old 11-17-2005, 02:04 AM   #35
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Default Re: 1 = 2

Quote:
Originally Posted by root
AČ = AB
AČ - BČ = AB - BČ
(A + B)(A - B) = B(A - B)
A + B = B
B + B = B
2B = B
2 = 1


OK, I'll try doing it with numbers
A = B = 1

AČ = AB => 1*1 = 1*1 => 1
AČ - BČ = AB - BČ => 1 - 1 = 1-1 => 0
(A + B)(A - B) = B(A - B) = (1+1)(1-1) = 1(1-1) =>true 0=0!!! (sure enough!)

1+1 = 1 False...

OK, now I'll try with a different number

A = B = 2

AČ = AB => 2*2 = 2*2 => 4
AČ - BČ = AB - BČ => 4 - 4 = 4-4
(A + B)(A - B) = B(A - B) = (2+2)(2-2) = 2(2-2) =>True

(2+2)(2-2)=>2*2 + 2*2 -2*2 - 2*2 = 0
2(2*2) = 4-4 = 0

2+2 = 2 False...

Like I said...
[/i]

The line (A + B)(A - B) = B(A - B) only works because both sides are equal(and equal to zero).
taking it past that is impossible...

therefore the solution only has real answers if A and B = 0

the maths is fine, and can be solved, but like I said, it only has 1 possible real solution.


there are no imaginary solutions either, I just tried...

Damm....I come home with a bad head ach to find this? WTF? A=B=A? Ah...I need a beer

Carry on, and regard this post, as it has no meaning to this thread, so it will be considered spam, but why am I still typing? See, still typing. Now this is considered spam, off topic, and has nothing to do with maths. So this is to prove I am very drunk or very tired. Right now, I'll just stop typing, and let the maths people handle this, since I am fully incapable of doing this. My mind has wondered off once again, and this post will still remain as a useless part of this thread. Oh well, mine as well have some math in it………Forget it, I’m too tired…..1+1=2  there you have it, some math for ya


And I come to read the crap I have just wrote. I’m sure one of the moderators will read this………Plus the math problem I have just did was not even relevant to this thread??? Jeese…I need some rest. Bye Bye now.

Ahh...so much crap
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Old 11-17-2005, 07:45 AM   #36
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Default Re: 1 = 2

OK. OK...


let me repeat...
A + B = B
B + B = B
2B = B
2 = 1

only works because the equation can be solved by using a = b = 0

the final two lines though.

2b = b

is actually saying that 2 * b (where b is an unknown quantity) = 1* b (same unknown quantity).


so logically b must = 0.
thats the only possible solution,
the equation does not say that 2 = 1.

thats just taking it a step too far...

the equation works algebraically, only when a = b = 0,
but for no other answer...

as I said before, this is because earlier in the equation both sides are canceled to zero.



The equations does nothing to proove anything is untrue.
simply because in Algebra the letters are used to represent unknon quantities, with the hope of finding out what those quantities are.
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Old 11-17-2005, 07:55 AM   #37
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Default Re: 1 = 2

Well, the proof still works as you can see. And A and B don't have to be zero. They can be any number as long as they are equal.
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Old 11-17-2005, 08:44 AM   #38
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Default Re: 1 = 2

No, I said the equation only works when A and B = 0...

I also said algebra is a tool for finding out unknown quantities and values, given a possible number of unknowns.

the equation 2b = b is a perfectly valid equation.
BUT
only if b=0...

2b is like saying 2 * b

b is like saying 1*b....


the only way you could use that equation to say that 2b = b is if b=0...

there is no other way to describe what is giong on you can't just say 2 = 1 because 2 multiplied by and unknown = 1 multiplied by an unknown...


The proof is all well and good,
and I told you why, (in the arrangement you gave) and and B do have to equal zero.
Quote:
Originally Posted by de-ja-vu
(2+2)(2-2)=>2*2 + 2*2 -2*2 - 2*2 = 0
2(2*2) = 4-4 = 0
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Old 11-17-2005, 08:49 AM   #39
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Default Re: 1 = 2

OK... I see where you are perhaps loosing me...


(A + B)(A - B) = B(A - B)
a - b = 0 you can't divide
by zero (unles the numerator is also 0)...

which messes up that step a+b = b

is quite valib since a+b is either infinity (which is not true) or zero...


which as I said is the only possible real answer that hold true with that equiation.


IS that perhaps easier to follow as to why I am saying the only real value for which the equiation can be solved numerically is if the equation = 0...

and since A and b are the two unknonws (but we know they are both equal) that algebraically they can only equal zero, given the equations you are trying to force them into.
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Old 11-17-2005, 09:58 AM   #40
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Default Re: 1 = 2

Quote:
Originally Posted by root
OK... I see where you are perhaps loosing me...


(A + B)(A - B) = B(A - B)
a - b = 0 you can't divide
by zero
DING DING DING! That's the correct answer. Since A and B are equal, factoring the (A - B) term would be - in effect - dividing by zero. That is the only thing that makes the proof invalid. Otherwise, it would be 100% true. A and B aren't limited to zero in the proof either. They can be any number. So yeah.... yay... mushroom hug time.
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