networking homework question

firemouse

Beta member
Messages
5
Location
N. Van
Comp 1
IP Address: 192.168.12.113
Subnet Mask: 255.255.255.0
Default Gateway: 192.168.12.1

Comp 2
IP Address: 192.168.12.205
Subnet Mask: 255.255.255.0
Default Gateway: 192.168.12.1

Comp 3
IP Address: 192.168.12.97
Subnet Mask: 255.255.255.0
Default Gateway: 192.168.12.1



Are these computers on the same network? Why or why not? If somthign is wrong what is the problem?
 
Yes, they are all on the same network.

Why: Because each of the IP addresses is 192.168.12.xx

Is something wrong? Not really, but these are static IP addresses, set by the person that configured each computer. I can tell, simply because they are spread so far out, 97, 113, 205. When you are using DHCP, your router will assign the next available IP address. It wouldn't be uncommon for them to be in order.
 
They all appear to be on the same network seeing they have the same Gateway, Mask, and 192.168.12.XXX IP Sequence. Looks to be some type of home network behind a router.
 
they are

192.168.12.113
255.255.255.0

192.168.12.205
255.255.255.0

192.168.12.97
255.255.255.0

all 3 have the same masking for subnet. So if all have 255.255.255.0. first 3 octets (192.168.12) say what network they are on, and the last octet (12, 203, or 97) says what the host is.

If the subnet mask has only 255 or 0's in it just line up the mask with the ip and match the number sets.

if the subnet has any other numbers like 255.255.255.192 then you will need to do math. Did you learn binary yet? you will need it for this part

are these on same subnet?
192.168.12.1
or
192.168.12.60
or
192.168.12.25
or
192.168.12.30
or
192.168.12.31

all have subnet mask of 255.255.255.224

the 255's all line up (255.255.255 and 129.168.12) but does the last octet (60,25,30,01,24)

In binany

001 = 00000001
025 = 00011001
030 = 00011110
031 = 00011111
032 = 00100000
060 = 00111100

Subnet mask
224 = 11100000

see how 1,25,30,31 all start with 000xxxxx and see how 224 starts with 111xxxxx?

if the 1's in the subnet mask line up with 0's in the left side of the host address then they are on the same subnet

so 192.168.12.1 - 192.168.12.31 are on the same subnet.
 
bilbus said:
if the subnet has any other numbers like 255.255.255.192 then you will need to do math. Did you learn binary yet? you will need it for this part

are these on same subnet?
192.168.12.1
or
192.168.12.60
or
192.168.12.25
or
192.168.12.30
or
192.168.12.31

all have subnet mask of 255.255.255.224

the 255's all line up (255.255.255 and 129.168.12) but does the last octet (60,25,30,01,24)

In binany

001 = 00000001
025 = 00011001
030 = 00011110
031 = 00011111
032 = 00100000
060 = 00111100

Subnet mask
224 = 11100000

see how 1,25,30,31 all start with 000xxxxx and see how 224 starts with 111xxxxx?

if the 1's in the subnet mask line up with 0's in the left side of the host address then they are on the same subnet

so 192.168.12.1 - 192.168.12.31 are on the same subnet.



geeez, i didnt think anyone actually uses this, much less remembers after studying and passing all 7 tests for an MCSE...
 
My network is subneted so i cant forget :p

its not that bad, just as long as your not dealing with lots of subneted networks
 
bilbus said:
Come on i just tought you how to subnet ... no thanks?

Actually, you just repeated what was already said in the first three posts prior to your arrival, just with a bit more info than may have been required. I figure that the other 2 people who posted before you (along with me) know something about subnetting ... hence their ability to answer the original question correctly.
 
Back
Top Bottom