Need math help

[Celticsfan]

I have a file that is 2,618,793,984 bytes in size. I need to break it into 5 to 7 files broken into MB. How many MB do I need to make each file? I need it to be broken into an even integer. No .#### left over. Can the math guru's help me out plz. If needed you can break it into bytes instead.

thx

 

[StratosP]

You could break it up into 6 files and then you'll have:
436465665 bytes in each file.

All I did is:
2,618,793,984 divided by 5 = 436465665

If you convert it to MB though it has a decimal point.

 

[JogaBonito1502]

1024 bytes in 1 Kilobyte.
1024 Kbytes in 1 Megabyte

2,618,793,984 / 1024 = 2,557,416

2,557,416 / 1024 = 2497.47

Now divide that number by 5, 6, or 7. Depending on how many files you want to break it up into.

 

[_-..zKiLLA..-_]

go joga go joga

 

[JogaBonito1502]

Dude...math is with me lol.

 

[StratosP]

Dude...math is with me lol.

Ha, I failed my Maths exam because I didn't study

 

[CrazyTiger]

1024 bytes in 1 Megabyte.

2,618,793,984 / 1024 = 2,557,416

Now divide that number by 5, 6, or 7. Depending on how many files you want to break it up into.

epic fail

1024 bytes in a kilobyte, 1024 KB in a MB, 1024 MB in a GB

 

[JogaBonito1502]

Oops...I was short lol. I knew something was wrong.

edit: Let me fix.

 

[CrazyTiger]

the whole bit\byte thing is much like the rest of the imperial system (the system of measures the US uses). There not very practical.

1024 was used for a reason though, tough to explain so ill just write this

2^10 = 1024

there are only two types of data, 1s and 0s, so the system does make some sense

 

[JogaBonito1502]

the whole bit\byte thing is much like the rest of the imperial system (the system of measures the US uses). There not very practical.

1024 was used for a reason though, tough to explain so ill just write this

2^10 = 1024

there are only two types of data, 1s and 0s, so the system does make some sense

Binary. But binary is grouped every 8 numbers. So I'm not so sure where you're getting 2^10 from.