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I don't know what Algebra you're learning, but you never assume parenthesis...

college?
the books, and example teacher gives are always shown like what i posted.
I got that equation straight off of my textbook by the way.
 
You can't just assume there's a parenthesis when you put an algebraic equation on a computer. You can get so many different combination of formulas. On the other hand...if you writing on paper and its something like x-2 then you assume parenthesis there. But if it's being divided and you have this:

x/3-y it's the same thing as (x/3) - y (following the little rule of order). You can't just assume it's x / (3-y).
 
so i should of posted it like this?

x(2x-1)
______
3y-z

Let x=-4, y=3, and z=5

well, my friends got the same as me.
maybe its what you are learning that makes you solve the equation.

damn book.... :p
 
okay, try this

-x***** -4****** -18
_____ - ____ = __________
(-x+3) *(x-3)* *(x-3)(x+3)*

I dont really know if its correct or not. But lets see what people get. Theres suppose to be 2 numbers, but ignore the negative number outcome.


Answer should be.....


10


EDIT - doesnt seem like it comes out right...

Okay, ignore the *
 
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