Juice1 Fully Optimized Messages 2,946 Apr 2, 2008 #1 One # is 15 more then another. The sum of twice the larger and 3 times the smaller is 182. Find the numbers. so far i got y + 15 = x x + 3y = 182 Now what?
One # is 15 more then another. The sum of twice the larger and 3 times the smaller is 182. Find the numbers. so far i got y + 15 = x x + 3y = 182 Now what?
JogaBonito1502 Guru Messages 7,841 Location U.S. Apr 2, 2008 #2 solve for y on both, then substitute. find x. use x to find y.
superman22x Golden Master Messages 7,904 Apr 2, 2008 #3 y + 15 = x 2x + 3y = 182 3y = 182 - 2x (y = x - 15)*3 3y = 3x - 45 3x - 45 = 182 - 2x +2x +45 = +45 +2x -------------------- 5x = 227 x = 45.4 y + 15 = 45.4 y= 30.4 x=45.4
y + 15 = x 2x + 3y = 182 3y = 182 - 2x (y = x - 15)*3 3y = 3x - 45 3x - 45 = 182 - 2x +2x +45 = +45 +2x -------------------- 5x = 227 x = 45.4 y + 15 = 45.4 y= 30.4 x=45.4
Dark Night BSOD Messages 2,505 Apr 2, 2008 #5 Yea I am good at math. At first I thought I had it but I didn't. Oh well I got my own homework to do
superman22x Golden Master Messages 7,904 Apr 2, 2008 #6 The answer is in my problem. You need to set it up so both are: 3y = X then those two Xs equal each other, then you can solve for x in there, and substitute x in for y.
The answer is in my problem. You need to set it up so both are: 3y = X then those two Xs equal each other, then you can solve for x in there, and substitute x in for y.
sanka Daemon Poster Messages 943 Apr 2, 2008 #7 Y + 15 = X 2X + 3Y = 182 2(Y+15) + 3Y = 182 2Y + 30 + 3Y = 182 5Y + 30 = 182 5Y = 152 Y = 30.4 Y + 15 = X 30.4 + 15 = X X = 45.4 Y = 30.4 Plug it in.. 2(45.4) + 3(30.4) = 182
Y + 15 = X 2X + 3Y = 182 2(Y+15) + 3Y = 182 2Y + 30 + 3Y = 182 5Y + 30 = 182 5Y = 152 Y = 30.4 Y + 15 = X 30.4 + 15 = X X = 45.4 Y = 30.4 Plug it in.. 2(45.4) + 3(30.4) = 182
Bobert93 Fully Optimized Messages 2,449 Apr 3, 2008 #9 i feel so stupid not knowing any thing your talking about