math very odd

[GreatHype]

im doing distance formula right now and I keep getting prefect squares.
this is what ive done
square root of (40-40)^2+(18-60)^2
I got 42
can someone please check this to see if I did it wrong.

 

[GreatHype]

nvm i got a way to check...lol i feel so stupid.

 

[badninja3]

square root of (40-40)^2+(18-60)^2

it is 42.

btw, your sig is a bit long.

 

[root]

SQRT of (40-40)^2+(18-60)^2
= SQRT of (0)^2+(-42)^2
= SQRT of -42^2
= 42

negative numbers squared = postitive numbers.
you cant square a number and bring back a negative result

eg 1^2 = 1
-1^2 = 1
SQRT(1) = 1
SQRT(-1) = j (that's an imaginary (not real) number)

 

[GreatHype]

lol ok thanks.

 

[Rubber314Chicken]

no, actually, the sqare root of -1 is i, and imagionary number. You will learn more about that in Algebra2. Now go finish your geometry homework.

 

[GreatHype]

im in algebra lol I take geometry next year. I'm doing my algebra hw right now and it sucks. I hate parabolas but good think I have omnigraph so I can check my work =)

 

[lhuser]

IF you square root a negative, it will give you an error. DO NOT try to do it if a question asks it. Just write impossible

 

[Bahawolf1]

If a square root was negative, it'd give you a value of i which is imaginary...

For example:
SQUARE ROOT -49 is..
7i.

 

[GreatHype]

in my case if the disciminant was negative I would automatically write no real solutions. We havent gotten to imaginary i's yet.